帮忙看看这道c语言编程题，关于do-while的

要求编一个程序，把1000到3000之间的阿拉伯数字转换成罗马数字，保持程序持续运行下去，直到用户输入“e”或者“E”。前面都不成问题，但是运行时，在while那里，直接循环，跳过让用户输入的选项。哪里有问题？帮忙看看。加急！！！！！！！谢谢

#include<stdio.h>
#include<iostream>
int main()
{
  char *a[][10]={"","I","II","III","IV","V","VI","VII","VIII","IX",
    "","X","XX","XXX","XL","L","LX","LXX","LXXX","XC",
    "","C","CC","CCC","CD","D","DC","DCC","DCCC","CM",
    "","M","MM","MMM"};
  int n, t, i, m, d, f;
  char asd;
  do
  {
    
      printf("Please enter an four-digit integer Arabic number from 1000 to 3000:");
      scanf("%d",&n); 
    
    printf("%d=",n);

    for(m=0, i=10000; m<4; m++, i=i/10)
    {
      d=n%i;
      f=i/10;
      t=d/f; 
      printf("%s", a[3-m][t+1]); 
    }

    printf("\n");
    printf("Press Enter to continue. If you want to end this program, please enter 'e' or 'E'.\n");
    asd=getchar();
    printf("\n");
  }while(!(asd='e'||'E'));
  system("pause");
  return 0;
}

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l***

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