(2) f(π/3-x)=f(π/3+x), ∴ f[π/3-(x-π/3)]=f[π/3+(x-π/3)],即 f(2π/3-x)=f(x), ∴ √5sin(4π/3-2x+Φ)=√5sin(2x+Φ) sin(2x+Φ)+sin(π/3-2x+Φ)=0,化积得sin(π/6+Φ)cos(2x-π/6)=0与x无关, ∴ sin(π/6+Φ)=0, π/6+Φ=kπ, 取k=0,得Φ=-π/6 (1) f(π/3)=√5sin(2π/3-π/6)=√5 (3) f(x)=√5sin(2x-π/6),-π/6≤x≤π/6, -π/2≤2x-π/6≤π/2, -1≤sin(2x-π/6)≤1, -√5≤f(x)≤√5 最大值√5, 最小值-√5
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