一道数学解方程
解下面方程: (x-4)^2 +2(x+1)=0x^2-8x+16+2x+2=0x^2-6x+18=0判别式=6^2-4*18=-36<0方程无实解.
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(x-4)^2 +2(x+1)=0 x^2-8x+16+2x+2=0 x^2-6x+18=0 判别式=6^2-4*18=-36<0x=3+9/2i或x=3-9/2i
x-4)^2 +2(x+1)=0 x^2-8x+16+2x+2=0 x^2-6x+18=0 判别式=6^2-4*18=-36<0
答:写成(3x+2y)/4=(2x+y)/5 ① ; (3x+2y)/4=(x-y+1)/6 ② 由①5(3X+2Y)=4(2X+Y) 由② 3(...详情>>