2乘以x的三次方减3乘以x的平方加1=0 怎么解
2乘以x的三次方减3乘以x的平方加1=0 怎么解
解:2x^3-3x^2+1=0 2x^3-2x^2-x^2+1=0 2x^2(x-1)-(x^2-1)=0 2x^2(x-1)-(x-1)(x+1)=0 (x-1)(2x^2-x-1)=0 x-1=0 得: x1=1 或2x^2-x-1=0 得: x2=-1/2 x3=1 综上: x1=x3=1 x2=-(1/2)
解:2x^3-3x^2+1=0 2x^3-2x^2-x^2+1=0 2x^2(x-1)-(x^2-1)=0 2x^2(x-1)-(x-1)(x+1)=0 (x-1)(2x^2-x-1)=0 (2x+1)(x-1)^2 =0 解得:x1=-1/2,x2=x3=1
问:(x+1)乘以(x+2)乘以(x+3)乘以(x+4)乘以(x+5)=a+bx+c*(x平方)
答:(x+1)乘以(x+2)乘以(x+3)乘以(x+4)乘以(x+5)(x+5)后乘以(x+6)乘以(x+7)乘以(x+8)乘以(x+9)乘以(x+10) =a+b...详情>>
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