对数计算
log[(1-根号2)这是底数](3+2*根号2)
1-√2=(1-√2)(1+√2)/(1+√2)=-1/(1+√2) 令1-√2=A 则1+√2=-1/(1-√2)=-1/A 3+2√2=(1+√2)^2=(-1/A)^2=(1/A)^2=A^(-2) log(1-√2)^(3+2√2)=logA^(3+2√2)=-2
log[(1-根号2)这是底数](3+2*根号2) =lg(3+2*根号2)/lg(1-根号2) =lg(1-根号2)^2/lg(1-根号2) =2lg(1-根号2)/lg(1-根号2) =2
答:lg√2+lg√5+log3(1) =lg(√2*√3)+0 =lg√10 =(1/2)lg10 =(1/2)*1 =1/2.详情>>
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