求不定积分
1.∫dx/根号下x* (1+三次根号下x) 2.∫dx/根号下(2x+1)-四次根号下(2x+1)
1.∫dx/根号下x* (1+三次根号下x) 令t=六次根号下x,则x=t^6, ∫dx/根号下x* (1+三次根号下x)=∫6t^2/(1+t^2)dt=6∫[1-1/(1+t^2)]dt=6t-6arctant+C=6×六次根号下x-6arctan六次根号下x+C 2.∫dx/根号下(2x+1)-四次根号下(2x+1) 令令t=四次根号下2x+1,则x=(t^4-1)/2,dx=2t^3dt, ∫dx/根号下(2x+1)-四次根号下(2x+1) =∫2t^2/(t-1)dt =2∫[t+1+1/(t-1)]dt =t^2+2t+2ln|t-1|+C =根号下(2x+1)+2四次根号下(2x+1)+2ln|四次根号下(2x+1)-1|+C
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