算度数
如图,求∠A+∠B+∠C+∠D+∠E+∠F的度数。
∠A+∠B+∠1+∠C+∠D+∠3+∠E+∠F+∠2=180*3=540, ∠1+∠2+∠3=180, ∠A+∠B+∠C+∠D+∠E+∠F=∠A+∠B+∠1+∠C+∠D+∠3+∠E+∠F+∠2-(∠1+∠2+∠3)=360
解: ∠A+∠B+∠AMB = 180(度) ∠C+∠D+∠COD = 180(度) ∠E+∠F+∠ENF = 180(度) 又 ∠AMB = ∠NMO ∠COD = ∠MON ∠ENF = ∠ONM 且∠NMO +∠MON+∠ONM =180(度) 所以 ∠A+∠B+∠C+∠D+∠E+∠F =180(度)*3 -(∠AMB+∠COD+∠ENF) =180(度)*2 =360(度)
答:详情>>