1)等于多少lim(x→0)(tanx?
lim(x→0)(tanx-sinx)/x(√1+x2-1)等于多少
im(x→0) lnx/lnsinx=lim(x→0) (sinx)/x × lim(x→0) 1/cosx=1
x→0时(tanx-sinx)/{x[√(1+x^2)-1]} =tanx/x*(1-cosx)[√(1+x^2)+1]/x^2 →4[sin(x/2)]^2/x^2 →1.
[路过这儿]
答:(22+1/20)*1/21 =[21+(1+1/20)]*1/21 =[21+(21/20)]*1/21 =21(1+1/20)*1/21 =1+1/20 =...详情>>
答:详情>>