ln(X+√1+x2)如何求导
ln(X+√1+x2)如何求导
(ln(x+√(1+x^2)))' =(x+√(1+x^2))'/(x+√(1+x^2)) =(1+2x/(2√(1+x^2)))/(x+√(1+x^2)) =1/√(1+x^2)
[1+ x (1+x2)^(-1/2)]/[X+√(1+x2)]
[ln(x+√(1+x²))' =[1/(x+√(1+x²)]×[x+√(1+x²)]' =[1/(x+√(1+x²)]×[1+(1/2)×1/√(1+x²)×2x] =[√(1+x²)]/(1+x²)
答:y=ln[x+√(x^2+a^2)] y'={1/[x+√(x^2+a^2)]}[x+√(x^2+a^2)]' ={1/[x+√(x^2+a^2)]}{1+(1...详情>>
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